FORCE TABLE (VECTORS) for PhysMoVan Students (Prof. Julia Thompson, May 3, 2003) Vectors are all around us, and important for making many things in our lives work. A few examples are: Holding up bridges, so they don’t fall down. A wheel rolling down an incline. Planes or boats travelling in an air or water current. With this force table we can study vectors, and learn a little about them. We will also learn about how to calibrate equipment, and about drawing graphs. This lab can be done in two ways. The first way assumes that students have already learned trigonometry. The second does not. But to begin with, both ways are the same. Step 1: Calibrate your springs. Adjust them so that they read zero when no force is applied. Then, put the one marked “1” along zero degrees, and the one marked “2” opposite it. Secure the “1”, and pull “2” until they balance. Pull until “1” reads 100 g, 200 g, 300 g, and 400 g. Make a table of the results. Now do the same thing for “1” and “3”. Read the values on the springs as well as you can and put down your estimate of the uncertainty. In order to complete the lab, you will need this uncertainty. You can judge the uncertainty Either by re-doing a measurement, or by having first you, then your partner make the measurement. Be czreful of “parallax”, which is the effect that if you tilt your head at different angles, you may find that the value of the reading changes. Step 2: If the vectors are all at equal angles from each other (in our case 120 degrees), and the system is in equilibrium, the magnitudes of the vectors will be equal. (Those of you who have had trigonometry can prove this; others may be able to think it makes sense using the idea of “symmetry”… if one is larger than the others, which one could it be? Check this configuration for your setup. Does the conclusion hold? Be sure to take uncertainty in your readings into account, and also, if necessary, your calibration curves: it may be that 150 g. on one spring corresponds to 152 g (eg) on another spring. Step 3: Put one spring at zero degrees, and put the other two at +/- the same angle wrt. 180 degrees. (We would try putting them both at 180 degrees next, but the springs are too bulky, and won’t fit). Here is where the students who have had trigonometry and have not will do something different. One can show, using trigonometry, that if A is along zero degrees, then B and C should have equal values. (if you have had trigonometry, your instructor will work with you to show this). But both groups can check this result as in Step 2, again taking your calibration curves and uncertainties into account. Step 4: If you have had trigonometry, you can show that A = 2 B cos(theta), where theta is the angle between B and 180 degrees. If you have not had trigonometry, you can still use the formula, and your instructor will help you find the cosine of theta. Check this condition as in steps 2) and 3), again taking your uncertainties (in both the angle and magnitudes of the vectors) into account. Step 5: DID IT WORK? CONGRATULATIONS? IF NOT… RECHECK YOUR CALIBRATION CURVES, MEASUREMENTS, AND UNCERTAINTIES! ( it will work in the end, if you get them rigtht)